![in honour of coining -or- the mile high club for logicians
i mentioned yesterday that i spent a good deal of my return flight questioning sachiv about his father’s reverse-œdipus issues. but what of my other flight? well, i WAS going to watch the benjamin button movie starring danny devito BUT on the day that i left, my father sent me this puzzle which i decided to work on instead.
you are given 12 coins. 1 of the coins is irregular and weighs either slightly more or slightly less than the other 11. you are also given an old-fashioned scale of the type that has come to symbolise the legal profession. your challenge is to determine which of the coins is irregular and if it weighs more or less than the others IN ONLY 3 ROUNDS OF WEIGHING ON THE SCALE.
it seemed easy enough but it took almost the entire 4 hour flight to arrive at an answer that still needed further retooling once i made it to a beach. if you can’t take the suspense, my solution is here [warning: the solution is A LOT more complicated than i originally thought].](http://28.media.tumblr.com/3FZnoU8PUojnemm1vRXOXepfo1_r1_500.png)
in honour of coining -or- the mile high club for logicians
i mentioned yesterday that i spent a good deal of my return flight questioning sachiv about his father’s reverse-œdipus issues. but what of my other flight? well, i WAS going to watch the benjamin button movie starring danny devito BUT on the day that i left, my father sent me this puzzle which i decided to work on instead.
you are given 12 coins. 1 of the coins is irregular and weighs either slightly more or slightly less than the other 11. you are also given an old-fashioned scale of the type that has come to symbolise the legal profession. your challenge is to determine which of the coins is irregular and if it weighs more or less than the others IN ONLY 3 ROUNDS OF WEIGHING ON THE SCALE.
it seemed easy enough but it took almost the entire 4 hour flight to arrive at an answer that still needed further retooling once i made it to a beach. if you can’t take the suspense, my solution is here [warning: the solution is A LOT more complicated than i originally thought].
